Question

Solution

题目大意:

两个字符串,其中一个字符串任意两个字符互换后与另一个字符串相等,只能互换一次

思路:

diff 记录不同字符数两个字符串长度不同 return false两个字符串长度相同:abc abd     无重复,diff == 1  ca[3] != cb[3] return falseabc abc     无重复,diff == 0  return falseab ba       无重复,diff == 2  return trueaa aa       aa重复,diff == 0  return trueaabc aabc   aa重复,diff == 0  return trueaacb aabc   aa重复,diff == 2  return true

Java实现:

public boolean buddyStrings(String A, String B) {    if (A.length() != B.length()) return false;    int[] ca = new int[26];    int[] cb = new int[26];    int diff = 0;    for (int i = 0; i < A.length(); i++) {        ca[A.charAt(i) - 'a']++;        cb[B.charAt(i) - 'a']++;        if (A.charAt(i) != B.charAt(i)) diff++;    }    for (int i = 0; i < ca.length; i++) {        if (diff == 0 && ca[i] > 1) return true;        if (ca[i] != cb[i]) return false;    }    return diff == 2;}